top | item 12170930 (no title) Pxl_Buzzard | 9 years ago A solution: everyone is sequentially numbered. Evens rotate left one round, odds rotate right the next round. That way everyone has to move the same amount (assuming an even number of participants). discuss order hn newest peteretep|9 years ago If I understand you correctly, not everyone then sees everyone else, which is likely to breed customer dissatisfaction flukus|9 years ago That's a pre-existing problem.
peteretep|9 years ago If I understand you correctly, not everyone then sees everyone else, which is likely to breed customer dissatisfaction flukus|9 years ago That's a pre-existing problem.
peteretep|9 years ago
flukus|9 years ago