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tatterdemalion | 8 years ago
This comment suggests you don't have much domain knowledge about how `unsafe` in Rust works, so I'm surprised you speak with such confidence. Your comment is flatly wrong: users using only safe code are not responsibility for guaranteeing the composed safety of the components they use (whether or not they are implemented with unsafe code).
Interfaces marked safe must uphold Rust's safety guarantees, or they are incorrect. They are just wrong if they have additional untyped invariants that need to be maintained to guarantee their safety; interfaces like this must be marked `unsafe`.
Because they cannot depend on untyped invariants, any correct implementation with a safe interface can be composed with any other. This ability to create safe abstractions over unsafe code which extend the reasoning ability of the type system is a fundamental value proposition of Rust.
klodolph|8 years ago
I hate being tone police, but jeez, we're having a discussion about Rust here and talking about my personal competency is inappropriate and unwelcome.
The problem I'm talking about happens when you write libraries that contain "unsafe" blocks. You want to prove (or at least assure yourself) that no unsafe behavior is observable by clients of the library. However, the way to do this is not entirely clear, although there is research being done in this area. One known trap is that it is not sufficient to demonstrate that Rust code without "unsafe" blocks cannot observe unsafe behavior in your library.
See: https://plv.mpi-sws.org/rustbelt/popl18/paper.pdf
These concerns are not hypothetical, there have been soundness problems in the Rust standard library before and I expect it to happen again.
tatterdemalion|8 years ago
Users of safe Rust do not need to worry about whether the composition of two safe interfaces that use unsafe internally is safe unless one of those interfaces is incorrect. Your comment would suggest that users need to think about the untyped invariants of each library they use, but this is not correct, libraries are not allowed to rely on untyped invariants for the correctness of their safe APIs.
dbaupp|8 years ago
I'm curious: what does this mean/could you point me to the part of the paper that describes it? (Unfortunately, I don't have time to read all 34 pages at the moment.)
wickawic|8 years ago
adwhit|8 years ago
If there is any way in which a function containing an `unsafe` block may be used unsafely (specifically, violating memory-safety), then that function must also be marked as unsafe.
tatterdemalion|8 years ago