(no title)
dsp1234 | 7 years ago
Hydrogen storage is "Approx. 5.0 kg"
122.4L of volume (60L front, 62.4L rear)
pressure is between 70 MPa and 87.5MPa
Doing the math shows:
density of hydrogen at 70MPa equals 36.69 g/L [1]
122.4L at 36.69 g/L equals 4.49kg [2]
density of hydrogen at 87.5MPa equals 45.96 g/L [3]
122.4L at 45.96 g/L equals equals 5.63kg [4]
So the amount is somewhere between 4.5kg and 5.63kg, depending upon the final pressure after filling. Which seems to line up squarely with "Approx. 5.0kg".
[0] - https://pressroom.toyota.com/releases/2016+toyota+mirai+fuel...
[1] - http://www.wolframalpha.com/input/?i=density+of+hydrogen+at+...
[2] - http://www.wolframalpha.com/input/?i=122.4L+at+36.69+grams%2...
[3] - http://www.wolframalpha.com/input/?i=density+of+hydrogen+at+...
[4] - http://www.wolframalpha.com/input/?i=122.4L+at+45.96+g%2FL
amluto|7 years ago
theptip|7 years ago
National Institute of Standards and Technology, NIST Reference Fluid Thermodynamic and Transport Properties Database (REFPROP)
https://www.nist.gov/srd/refprop
I.e. these are standard reference curves at a fixed temperature.
If you click the link on "Hydrogen" you get a page for molecular hydrogen, H2, so not an isotopic mix. Whether that's the right input for this calculation is beyond my technical knowledge, but Wolfram is displaying its parameters quite straightforwardly.
To my reading it looks like a quite well-explained calculation, though I can see why you might think otherwise if you hadn't spotted the somewhat-hidden "sources" link.
avmich|7 years ago
Surely van der Waals should provide a better model here, as we're having pretty dense gas which is far from ideal. So I'd assume it should be van der Waals model; not sure what Wolfram Alpha actually does.