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dsp1234 | 7 years ago

The spec sheet at [0] claims:

Hydrogen storage is "Approx. 5.0 kg"

122.4L of volume (60L front, 62.4L rear)

pressure is between 70 MPa and 87.5MPa

Doing the math shows:

density of hydrogen at 70MPa equals 36.69 g/L [1]

122.4L at 36.69 g/L equals 4.49kg [2]

density of hydrogen at 87.5MPa equals 45.96 g/L [3]

122.4L at 45.96 g/L equals equals 5.63kg [4]

So the amount is somewhere between 4.5kg and 5.63kg, depending upon the final pressure after filling. Which seems to line up squarely with "Approx. 5.0kg".

[0] - https://pressroom.toyota.com/releases/2016+toyota+mirai+fuel...

[1] - http://www.wolframalpha.com/input/?i=density+of+hydrogen+at+...

[2] - http://www.wolframalpha.com/input/?i=122.4L+at+36.69+grams%2...

[3] - http://www.wolframalpha.com/input/?i=density+of+hydrogen+at+...

[4] - http://www.wolframalpha.com/input/?i=122.4L+at+45.96+g%2FL

discuss

order

amluto|7 years ago

I am highly skeptical of using Wolfram Alpha like this. It steadfastly refuses to explain how it got its answer or what sources it used. These are high pressures and large densities. Are these results of an ideal gas law calculation? Are they results from the van der Waals equation? Are they extrapolated from actual experimental data? If so, what experiment? What are the error bars? Are they talking about pure Hydrogen-1 or are they talking about the isotopic mix found in sea water? (The latter is a small correction, but it’s still something that they should explain on the site.)

theptip|7 years ago

If you hover over the "Variation with temperature at constant pressure" chart you get a "sources" link, which references

National Institute of Standards and Technology, NIST Reference Fluid Thermodynamic and Transport Properties Database (REFPROP)

https://www.nist.gov/srd/refprop

I.e. these are standard reference curves at a fixed temperature.

If you click the link on "Hydrogen" you get a page for molecular hydrogen, H2, so not an isotopic mix. Whether that's the right input for this calculation is beyond my technical knowledge, but Wolfram is displaying its parameters quite straightforwardly.

To my reading it looks like a quite well-explained calculation, though I can see why you might think otherwise if you hadn't spotted the somewhat-hidden "sources" link.

avmich|7 years ago

At least Wolfram Alpha agrees with Toyota data.

Surely van der Waals should provide a better model here, as we're having pretty dense gas which is far from ideal. So I'd assume it should be van der Waals model; not sure what Wolfram Alpha actually does.