[likeliv]

Is that not an undefined behaviour?

Can't you get some values "out of thin air" (partial updates of some bits.) Or some intermediate values?

(For example, can the compiler decide to use this memory location to store some unrelated temporary result, as it knows it will erase it soon with a final value and that no other threads is supposed to access this)

[lilyball]

It's not undefined because the thread doing the reading is the same one that wrote the value in the first place, meaning there is no cross-thread behavior at the moment and therefore the memory model collapses down to the single-threaded model (where all atomic accesses are irrelevant).

[carllerche]

The compiler cannot use the contents of an `UnsafeCell` for temporary storage. In general, `UnsafeCell` is how data can be shared across threads without synchronization.

[CodesInChaos]

I thought `UnsafeCell` is only exempt from the aliasing rules, not the memory model? I.e. the compiler can use it as it wants, if it can prove that it's not accessed in the meantime (which can be difficult without relying aliasing rules, but possible if the code is simple enough)

[BubRoss]

In x86 at least, 32 bit loads and stores are done atomically already.

[likeliv]

I know rust is not C or C++, but we are not programming in x86 assembly, but for the language "abstract machine". And if the compiler infer that this memory location is not used by other threads because we don't use an atomic operation, it can perform optimizations that could result in subtle bugs. That's what undefined behaviour is.

Although in this case, I guess this is probably fine since the non-atomic read can't race with a write.

[charliesome]

x86 does do out-of-order execution however, so while it's true that you'll never read a half-written value, it's still important to use the atomic types to ensure that reads/writes across threads are performed in the right order.