[Kutta]

What you say is kind of interesting but I get the impression that we are talking past each other.

id(X): ==(X, rec_0(0, X))

Sorry, what's this supposed mean, is it a definition? The propositional equality type has two or three arguments, I only see one (X) here, if as you say "id" is propositional equality.

In any case, nothing peculiar happens when we check a trace-annotated proof of bottom. We are free to use any particular finite-step unfolding of the non-normalizing proof.

We also don't need any paradox or inconsistency for a non-normalizing term, it is enough to work in ETT in a typing context which implies bottom, or which contains an undecidable equational theory, e.g. the rules of the SK-calculus.

> The actual proofs of decidability of type checking (e.g. from Martin-Löf‘s original paper) are conditioned on the normalization theorem

Decidability of type checking is always relative to a particular surface/raw syntax. A trace-annotated raw syntax does not need a normalization assumption for type checking.

[johncolanduoni]

I left the first argument of the equality type implicit, written fully it’s ==(0, X, rec_0(0, X)) since those terms are both of type 0.

The overall expression is shorthand for any term whose typechecking involves that type assertion. For example, type checking passing the term to the left of the colon to an identity lambda with argument type of the term to the right of the colon (λ(x: ==(0, X, rec_0(0, X))).x)(id(X)) will pass iff the left term’s type is right term.

I’m not talking about extensional type theories here (as Idris/MLTT is not extensional), so I don’t think I understand the relevance of the trace annotated proof. Idris will let you write the term I have above without any trace annotations so its typechecker must do something with it.

You’re right that a trace-annotated raw syntax doesn’t need normalization assumptions, but Idris is not trace annotated; the type checking algorithm is required to perform any normalization required without further direction from the user.