(no title)
sonofgod | 5 years ago
Let's assume that the baby has a perfect ordered ranking of blocks, 3 > 2 > 1, but that the experimenter doesn't know what it is.
There's three scenarios for what the new, third block is: 1, 2 or 3.
If it's 2 or 3, then the rejected block in the first round has a score of 1, and so we'd expect. So we'd only expect the baby to switch in a third of the cases, as opposed to 50% of the cases where the blocks are assumed to be equal.
"However, in the critical test trial that followed, 16 of 21 infants (76.2%) chose the new block (block C; Fig. 1)"
I can't work out the p-value vs. 66% compared to 50%, though...
TimPC|5 years ago
MauranKilom|5 years ago