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ben509 | 4 years ago
Arguably the bigger problem is you don't know that the ransomer will actually give you a valid key, but suppose you guess a likelihood P that they do.
Now you have some scenarios:
1. Don't pay. We're out $C.
2. Do pay, and get a valid key. We're out $R.
3. Do pay, and get no key. We're out $R + $C.
So the limit is at scenario 1 being equal to the combination of 2 and 3.
Set C = PR + (1-P)(R + C), and your max ransom R = CP
(You could probably work in additional costs for cleaning up even if the ransom is paid.)
nstj|4 years ago