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Fatalist_ma | 4 years ago

There's nothing broken about parseInt. The problem is, it can take a second argument(radix), and .map will feed it current item's index as the second argument(and the whole array as the third, but that one will get ignored).

const arr = ['1','2','3']; arr.map(parseInt) is equivalent to: [ parseInt('1', 0, arr), parseInt('2', 1, arr), parseInt('3', 2, arr) ];

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antris|4 years ago

I know why it works this way. I'm not claiming it has a bugged implementation, I'm saying it's broken by design.