top | item 30955896 (no title) ivad | 3 years ago A measurement being 7 sigma out would still be Chebyshev bounded by 1/7^2 ≈ 0.02 I.e. the probability of it being ≥7 sigma out is interestingly at most 0.02. discuss order hn newest freemint|3 years ago Neat i didn't think about that. But that is less improbable then 1 in 12450197393 which is what you might get with normal distribution. lupire|3 years ago That's just because Chevyshev bounds is a very weak general statement about all distributions.High Energy Physics sigma is calibrated to match normal distribution quantiles. lupire|3 years ago That is not so interesting because it could be far less.
freemint|3 years ago Neat i didn't think about that. But that is less improbable then 1 in 12450197393 which is what you might get with normal distribution. lupire|3 years ago That's just because Chevyshev bounds is a very weak general statement about all distributions.High Energy Physics sigma is calibrated to match normal distribution quantiles.
lupire|3 years ago That's just because Chevyshev bounds is a very weak general statement about all distributions.High Energy Physics sigma is calibrated to match normal distribution quantiles.
freemint|3 years ago
lupire|3 years ago
High Energy Physics sigma is calibrated to match normal distribution quantiles.
lupire|3 years ago