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omegalulw | 3 years ago

This seems...wrong?

Let's say you can control voltage, cross section area A.

Now, you want a constant power across a load P = V * I.

Your net resistance R is C + D * L / A where C and D are constants and L is your cable length.

I is proportional go V * A / (C * A + E) where E is also a constant.

So your load power is proportional V^2* C * A / (C * A + E) which is proportional to V^2 * A / (A + F) where F is also a constant.

With a large "enough" A, this is effectively V^2. With a small A, this is V^2 * g where g is A / F. So the smaller the area you have the more power you are wasting (roughly equal to V^2 * (1-g) which is heat in the wires).

So the smaller area you have, the less efficient your power delivery. And juicing up your source power is a lot more expensive than juicing up your source voltage.

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