top | item 34441808 (no title) johnnny | 3 years ago As fro your further edit: assuming √2 is rational, then the set of ~~rational~~ integers {q: q√2 ∈ ℤ} does not admit a minimum, indeed it contains arbitrarily small numbers, so we can't pick k the smallest member of that set. discuss order hn newest No comments yet.
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