(no title)
de_keyboard | 3 years ago
Just replace this:
x |> f
With this: f(x)
For the join example, you must do this: xs
|> (x => x.join(' '))
It de-sugars to: (x => x.join(' '))(xs)
... which of course is simply: xs.join(' ')
captainmuon|3 years ago
Does join(a)(b) mean join(a, b) or join(b, a)? Does it mean a.join(b) or b.join(a)? And is a or b the delimiter? I don't really feel confident without looking it up or trying it out. I have a similar problem with Haskell's function syntax a -> a -> a.
If the function was called makeJoinerBy(sep)(array), it would be somewhat clearer: