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Linosaurus | 3 years ago
And perhaps also, “remember: Monty will always open a door, and the contestant knows it”.
Makes me wonder if there were similar shows where the host can choose not to open a door.
Linosaurus | 3 years ago
And perhaps also, “remember: Monty will always open a door, and the contestant knows it”.
Makes me wonder if there were similar shows where the host can choose not to open a door.
adhesive_wombat|3 years ago
If you choose the door with the car, the host will open another door to tempt you, so then you don't switch, unlike in traditional Monty Hall. And if he didn't open a door, well, that means you choose a goat, so you should switch for a 50% chance. Except the host knows you're thinking this. And you know he knows. And he knows you know he knows. And...
Perhaps, iterated infinitely, this eventually resolves into a limiting expected value for switching and not, but I have no idea how to compute such a scenario.
em500|3 years ago
em500|3 years ago
mcphage|3 years ago
And yet it is the subject of endless discussions. The optimum strategy is pretty easy to work out, yet not widely believed.