[protomikron]

> They use the printf "%f" float format conversion so `printf "%f" 2e3` will work just fine, whereas using something that definitively is not a float makes printf exit with an error code as it fails to format the value as float, failing this check.

You are of course correct (sorry to sound like a language model), I missed the printf.

[hddqsb]

Actually, the function returns success if the input contains "." and printf succeeds, so it does not consider 2e3 to be a float. I agree that this function is odd (it's not even useful for identifying simple numbers of the form "123.456", because it considers 2.0e3 to be a float).