top | item 36168385 (no title) tyler569 | 2 years ago And that ABI specific stack manipulation would be UB, so the optimizer can assume it doesn't happen. With no UB, that's not true. discuss order hn newest Dylan16807|2 years ago You assume a langue without UB would allow stack manipulation. But then it would have to be defined. How would you possibly define it fully? remexre|2 years ago There's an area of memory into which variables with automatic storage duration are allocated at implementation-defined addrs, at any point exactly those variables have addresses. load replies (1)
Dylan16807|2 years ago You assume a langue without UB would allow stack manipulation. But then it would have to be defined. How would you possibly define it fully? remexre|2 years ago There's an area of memory into which variables with automatic storage duration are allocated at implementation-defined addrs, at any point exactly those variables have addresses. load replies (1)
remexre|2 years ago There's an area of memory into which variables with automatic storage duration are allocated at implementation-defined addrs, at any point exactly those variables have addresses. load replies (1)
Dylan16807|2 years ago
remexre|2 years ago