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anthony88 | 2 years ago

As a non physicist here, why not showing a video of a ohmmeter showing zero's when measuring the resistance of this material instead of its levitation?

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segfaultbuserr|2 years ago

A Meissner effect demo is usually seen as an easier and stronger proof of superconductivity than a resistance measurement, which is a delicate task and susceptible to experimental errors.

First, one cannot measure superconductivity with an ordinary ohmmeter. Electrodes, wires and the ohmmeter itself are resistive, the meter can never show zero ohms. So you can't just look at the screen read-out and say there's superconductivity, you need to set an experiment up to do it manually, with a current source and a voltmeter to measure the IV curve across the material [1]. Even then, the voltmeter will never show "zero" volt because of noise, such as thermocouple effect, triboelectric effect, or electromagnetic interference - which need to be minimized during the experiment and removed during post-processing. There are also the problems of sample preparation and purity as others have noted.

[1] It's basically the same 4-wire Kelvin sensing used by all milli-ohmmeters. But to characterize superconductivity, you need to do even better. https://en.wikipedia.org/wiki/Four-terminal_sensing

Out_of_Characte|2 years ago

Look at how tiny the spec is. What would be the most convincing evidence? A resistence meter that basacally touches itself or a spec clearly floating on a magnet without cooling.

netheril96|2 years ago

My guess is that it needs to be very pure to have zero resistance. But levitation requires less purity.

out_of_protocol|2 years ago

Way too easy to fake. Too many places to modify, including non-obvious like ohmmeter mode or firmware

Kenji|2 years ago

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