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bigcheesegs | 2 years ago
In C++ there's actually a lot more freedom. You can access non-atomic non-volatile-std :: sig_atomic_t variables as long as you don't violate the data race rules.
bigcheesegs | 2 years ago
In C++ there's actually a lot more freedom. You can access non-atomic non-volatile-std :: sig_atomic_t variables as long as you don't violate the data race rules.
jlokier|2 years ago
Not really. The two languages are similar on this. The 'volatile' before 'sig_atomic_t' is still required in C++ for the same reasons as C. You can access non-volatile sig_atomic_t variables in C too, but in both languages that's not enough for the signalling that type exists for, so you have to use 'volatile sig_atomic_t', in C and C++.
An example of scenario 1) is the loop below. The 'volatile' is required in C++ the same as in C. If you interrupt the loop below in C++ with a signal handler that updates 'flag', the loop is not guaranteed to exit unless 'flag' is declared volatile.
You can test this easily. Just now I compiled the C++ code below with Clang/LLVM with -O on a Mac, and GCC with -O on Linux. On both systems and compilers, Control-C fails to stop the process if 'volatile' is not used. If compiled without -O, Control-C always interrupts the process, but you can't rely on behaviour of disabled optimisations.
bigcheesegs|2 years ago
C however states :
> When the processing of the abstract machine is interrupted by receipt of a signal, the values of objects that are neither lock-free atomic objects nor of type volatile sig_atomic_t are unspecified, [...] The representation of any object modified by the handler that is neither a lock-free atomic object nor of type volatile sig_atomic_t becomes indeterminate when the handler exits.
This wording is not present in C++, as it instead defines how signal handlers fit into the memory model.
This means that (with adjustments for C atomics):
Is valid in C++, but not in C.gpderetta|2 years ago