top | item 37831183 (no title) jpeterson | 2 years ago The probability of [HEADS, TAILS] is always the same as the probability of [TAILS, HEADS], no matter how the coin is weighted. discuss order hn newest dataflow|2 years ago I get that but I don't see how it answers my question? arrowsmith|2 years ago You're flipping pairs of coins until you get either "HT" or "TT". So the only two possibilities are:1. keep flipping until you get HT (and so you choose 'heads') 2. keep flipping until you get TH (and so you choose 'tails')Since HT and TH are equally likely, results 1 and 2 are equally likely, i.e. there's a 50% chance of choosing heads, 50% change of choosing tails.
dataflow|2 years ago I get that but I don't see how it answers my question? arrowsmith|2 years ago You're flipping pairs of coins until you get either "HT" or "TT". So the only two possibilities are:1. keep flipping until you get HT (and so you choose 'heads') 2. keep flipping until you get TH (and so you choose 'tails')Since HT and TH are equally likely, results 1 and 2 are equally likely, i.e. there's a 50% chance of choosing heads, 50% change of choosing tails.
arrowsmith|2 years ago You're flipping pairs of coins until you get either "HT" or "TT". So the only two possibilities are:1. keep flipping until you get HT (and so you choose 'heads') 2. keep flipping until you get TH (and so you choose 'tails')Since HT and TH are equally likely, results 1 and 2 are equally likely, i.e. there's a 50% chance of choosing heads, 50% change of choosing tails.
dataflow|2 years ago
arrowsmith|2 years ago
1. keep flipping until you get HT (and so you choose 'heads') 2. keep flipping until you get TH (and so you choose 'tails')
Since HT and TH are equally likely, results 1 and 2 are equally likely, i.e. there's a 50% chance of choosing heads, 50% change of choosing tails.