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cbright | 2 years ago
Not constant time; the analysis in the paper shows that the nth digit can be computed in O(n log n M(log n)) bit operations, where M(j) is the bit complexity of multiplying two j bit numbers.
cbright | 2 years ago
Not constant time; the analysis in the paper shows that the nth digit can be computed in O(n log n M(log n)) bit operations, where M(j) is the bit complexity of multiplying two j bit numbers.
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