Can someone explain why it goes from strictly multiplication/division for Somos 1,2 and 3 but then at Somos 4 the addition operation is added? It seems completely arbitrary.
Are you talking about the behavior of the floor operator in determining the number of terms in the sum? For k in {1,2,3}, floor(k/2) = 1. So there would only be one term and thus no addition.
davesque|2 years ago
Are you talking about the behavior of the floor operator in determining the number of terms in the sum? For k in {1,2,3}, floor(k/2) = 1. So there would only be one term and thus no addition.
ghusbands|2 years ago