[neovialogistics]

It's not applicable. The theorem applies to the boundary of 1+2n dimensional balls - surface of an ordinary sphere, bulk of a 5-ball, 6-surface of a 7-ball, etc.

[vecter]

Why does the proton not meet this criteria?

[neovialogistics]

I see where my post above was unclear. For the theorem to apply to a 1+2n dimensional object, the vector field on the 2n dimensional surface of the object must be restricted to the surface - it must be tangent to the object everywhere.

The proton is fully 3-dimensional AFAICT so the vector field on the surface (if it has a surface, I'm not a physicist) can have non-tangent components, pointing inwards or outwards.