[kpreid]

A bit of disagreement with your last paragraph: The (Common) Lisp macro processor is Turing-complete trivially because it invokes a Turing-complete language along the way, not because of power inherent in its expansion strategy.

Common Lisp macro bodies are written in Common Lisp, i.e. written in a Turing-complete language — they would still be Turing-complete even if we wrote them in the subset Lisp-without-macros. The C preprocessor, on the other hand, does not invoke a Turing-complete language to compute a macro's expansion.