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PaulWaldman | 1 year ago

Anyone want to take a guess of the terminal velocity of a 737 Max?

discuss

order

its_ethan|1 year ago

Way higher than 35 m/s...

Using V = sqrt(2ma/pAC) you'd get:

V = sqrt(2(80000 kg)(9.81 m/s^2)/((1.225 kg/m^3)(210 m^2)(0.03)))

V = 451 m/s