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karatinversion | 1 year ago
f(n) = { 1 if there is a Turing machine with at most n states that solves the Halting problem;
0 otherwise }
and we can easily show that f(n) is computable without proving that the Halting problem is undecideable. Viz., f is either constant 0; or equal to a function of the form g_k(n) = { 1 if n >= k;
0 if n < k },
and both the constant 0 function, and all the g_k functions, are computable; thus f is computable.
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