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nikhilsimha | 1 year ago
For example - max over {4, 5} is 5. Now I update the 5 to a 3, so the set becomes {4, 3} with a max of 4. This seems to imply that the z-sets would need to store ALL the values - again, in their internal state.
Also there needs to be some logic somewhere that says that the data structure for updating values in a max aggregation needs to be a heap. Is that all happening somewhere?
lsuresh|1 year ago
Update from Leonid on current implementation: each group is ordered by the column on which we compute max, so it's O(1) to pick the last value from the index.
nikhilsimha|1 year ago
shuaiboi|1 year ago
they probably have a monotonicity detector somewhere, which can decide whether to keep all the values or discard them. If they keep them, they probably use something like a segment tree to index.
ryzhyk|1 year ago
lsuresh|1 year ago