(no title)
erwald | 1 year ago
from collections import defaultdict
def find_cheryls_birthday(possible_dates):
# Parse the dates into month and day
dates = [date.split() for date in possible_dates]
months = [month for month, day in dates]
days = [day for month, day in dates]
# Step 1: Albert knows the month and says he doesn't know the birthday
# and that Bernard doesn't know either. This implies the month has no unique days.
month_counts = defaultdict(int)
day_counts = defaultdict(int)
for month, day in dates:
month_counts[month] += 1
day_counts[day] += 1
# Months with all days appearing more than once
possible_months = [month for month in month_counts if all(day_counts[day] > 1 for m, day in dates if m == month)]
filtered_dates = [date for date in dates if date[0] in possible_months]
# Step 2: Bernard knows the day and now knows the birthday
# This means the day is unique in the filtered dates
filtered_days = defaultdict(int)
for month, day in filtered_dates:
filtered_days[day] += 1
possible_days = [day for day in filtered_days if filtered_days[day] == 1]
filtered_dates = [date for date in filtered_dates if date[1] in possible_days]
# Step 3: Albert now knows the birthday, so the month must be unique in remaining dates
possible_months = defaultdict(int)
for month, day in filtered_dates:
possible_months[month] += 1
final_dates = [date for date in filtered_dates if possible_months[date[0]] == 1]
# Convert back to original format
return ' '.join(final_dates[0]) if final_dates else "No unique solution found."
# Example usage:
possible_dates = [
"May 15", "May 16", "May 19",
"June 17", "June 18",
"July 14", "July 16",
"August 14", "August 15", "August 17"
]
birthday = find_cheryls_birthday(possible_dates)
print(f"Cheryl's Birthday is on {birthday}.")
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