[FranchuFranchu]

Happy new 2025 = (20 + 25)^2 = (2 + 0!)^2*5 = (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)^2 = 1^3 + 2^3 + 3^3 + 4^3 + 5^3 + 6^3 + 7^3 + 8^3 + 9^3

[cobbaut]

> = (2 + 0!)^2*5

How?

0! = 1 so how does 3^2*5 become 2025?

[mkl]

It doesn't, you need to square the whole thing.

[kappuchino]

(2 + 0!)^25 is only 45 on my account, should be ((2 + 0!)^25)^2 :-/