[likpok]

You don't need to require same-order initialization, but allowing people to do different orders will be confusing when actions are reordered behind the scenes. Especially imagine if there are dependencies between the objects you're passing in.

  struct A {
    B one;
    C two;
  };
  struct B {
    B() {
      cout << "init B" << endl;
    }
  }
  struct C {
    C() {
      cout << "init C" << endl;
    }
  }

Mixing up the order is confusing:

  A{.two=B(),.one=A()}

since `two` is initialized after `one` despite coming before (the comma operator <expr a>, <expr b> usually means `expr a` happens before `expr b`.

This case is a little contrived, but run the evolution forward: you can have members that depend on each other, or have complex initialization logic of their own. There, debugging the specific order of events is important.

[xmcqdpt2]

Scala does it by pulling out the keyword arguments to variables so that your example would become

{ val x$1 = B() val x$2 = A() A(.one = x$2, .two = x$1) }

This maintains left-to-right evaluation order while allowing you to pass arguments in any order.

There is probably some dark and forbidden reason why C++ can't do that.

ETA: That's basically what the post does.