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dcan | 11 months ago
It’s space-inefficient as half of the CPUs are shutdown, but architecturally it’s all on the same bus.
dcan | 11 months ago
It’s space-inefficient as half of the CPUs are shutdown, but architecturally it’s all on the same bus.
Aurornis|11 months ago
In practice is doesn't matter very much for a design like this. The size is already limited to a certain minimum to provide enough perimeter area to provide wire bonding area for all of the pins, so they can fill up the middle with whatever they want.
DrNosferatu|11 months ago
Narishma|11 months ago
enragedcacti|11 months ago
> The final die size would likely have been exactly the same with the Hazard3 removed, as std cell logic is compressible, and there is some rounding on the die dimensions due to constraints on the pad ring design.
https://nitter.space/wren6991/status/1821582405188350417
Graziano_M|11 months ago
[1] https://www.raspberrypi.com/news/security-through-transparen...
petertodd|11 months ago
myrmidon|11 months ago
Have seen the same (ARM + RISC-V cores) even at larger scales before (Milk-V Duo @1GHz-ish). But how is this economical? Is die space that cheap? Could you not market the same thing as quadcore with just minor design changes, or would that be too hard because of power budget/bus bandwidth reasons?
imtringued|11 months ago
bananapub|11 months ago
1) it needs a certain perimeter to allow all the pins to go from the silicon to the package, which mandates a certain sized square-ish die 2) only the cores are duplicated (and some switching thing is added)
so yes, there is enough space to just add another two cores without any worries, since they don't need more IO or pins or memory or anything.