(no title)
zfnmxt | 11 months ago
What if signal failures "add" 15%? Then all factors combined would mean that there's a 105% chance your train will be delayed!
Adding up probabilities like this doesn't make sense. If you simplify these things as independent events, the probability of delay is just the 1 minus the product of all the probabilities of each event not happening (i.e., 1 - P(event)).
As for the article---I think you really undervalue your time and the price of inconvenience. I can see how you can romanticize it as a nice way to get things done, but (dealing with) train delays is hardly distraction free and is full of forced setting changes and (very) shit working environments (like waiting on a platform). This is a bad deal, even if it's free. Money is there to to be spent; this is a instance in which to spend it, moral/ethical/fraud concerns aside.
But hey maybe you're a Von Neuman type and thrive in cacophony and chaos.
WindyMiller|11 months ago
ValentineC|11 months ago
By delays, I think the author meant that they get on a train, then sit in it for ~5 hours, with the option of paying roughly twice the price for first class [1].
As someone who frequently uses their laptop on public transport too, this sounds like a great way to either get things done or pass time.
[1] https://www.avantiwestcoast.co.uk/travel-information/onboard...
Doctor_Fegg|11 months ago
sveme|11 months ago
MathMonkeyMan|11 months ago
irjustin|11 months ago
Aeolun|11 months ago
The only experience I have was taking them in the other direction though, because I opted for a flight instead of dealing with it again to go back to London.
Was a new experience booking a train ticket and seeing a quote of £250. I thought the machine was broken.
tempfile|11 months ago
1-(1-p1)(1-p2) = p1+p2-p1p2
and a similar formula holds for more terms. so neglecting terms of order p^2 gives the form in the article
sebastiennight|11 months ago
But adding 10%, 20%, and 35%, is already a pretty bad start. The error rate becomes huge. (in the article example, the 10% estimate of chances of being on time is ~3.5 smaller than the actual 35% correct result).
Being wrong by half an order of magnitude, is being quite wrong :)