(no title)
Dor_Elbaz | 10 months ago
The model assumes infinite parallelism and zero overhead, isolating only the total amount of “logical work” an algorithm must perform. Even in this idealized setting, I prove that for all sufficiently large n, any correct algorithm solving SAT must perform Ω(2ⁿ) total work. Then, using a simulation lemma, I show that this lower bound implies SAT ∉ P, and therefore P ≠ NP.
The argument avoids known barriers like relativization, natural proofs, and algebrization. It’s formal, self-contained, and includes two appendices: one for cross-validation against known results, and one FAQ addressing common objections.
Here is Version 3 of the paper, incorporating all revisions and reviewer feedback so far: https://zenodo.org/records/15263845
I’d be thrilled to hear what you think — and grateful for any feedback, critiques, or questions.
— Dor Elbaz
mika6996|10 months ago
Dor_Elbaz|10 months ago
It’s currently being submitted to the ECCC and arXiv for formal review. I’ve also reached out to a few experts (including Scott Aaronson) and am actively seeking feedback.
I’d be thrilled to hear any comments or critiques you might have — peer review begins with open dialogue. Thanks for asking.