Starting at an initial density of air, suppose you descend a distance D such that the air density doubles. Now your air is twice as dense, which doubles the pressure underneath it, meaning if you descend a further D the density will double again. Continue ad infinitum (or at least until the ideal gas law stops being a good approximation).
> Pressure (P), mass (m), and acceleration due to gravity (g) are related by P = F/A = (m*g)/A, where A is the surface area. Atmospheric pressure is thus proportional to the weight per unit area of the atmospheric mass above that location.
skykooler|9 months ago
westurner|9 months ago
Two-body gravitational attraction is observed to be an inverse square power law; gravitational attraction decreases with the square of the distance.
g, the gravitational constant of Earth, is observed to be exponential; 9.8 m/s^2.
Atmospheric pressure: https://en.wikipedia.org/wiki/Atmospheric_pressure#:~:text=P... :
> Pressure (P), mass (m), and acceleration due to gravity (g) are related by P = F/A = (m*g)/A, where A is the surface area. Atmospheric pressure is thus proportional to the weight per unit area of the atmospheric mass above that location.
westurner|9 months ago
Are you donvoting according to preference or to Terms of Service?
nh23423fefe|9 months ago
> 40–1 The exponential atmosphere
https://www.feynmanlectures.caltech.edu/I_40.html