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antics | 8 months ago

Kind of, kind of not. I think it's fair to argue a lot of theory people would argue that it is effectively guaranteed to terminate, for any reasonable definition of "guaranteed."

As I mention elsewhere, for a coin where P(H)=0.75, with 600 flips, the probability of not having received an answer is less than 1 divided by the number of atoms in the universe. While this is not 0, neither is the probability of the atoms of the coin lining up just right that it falls through the table, producing neither H or T. Theoretically and practically we do generally consider these kinds of things immaterial to the problem at hand, perhaps papering over them with terms-of-art like "with high/extremely high/arbitrarily high/ probability". They all mean roughly the same thing: this algorithm is "essentially guaranteed" to terminate after n flips.

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