(no title)
derdi | 7 months ago
I would find the following a more convincing presentation:
theorem x_eq_x (x:nat) : x = x := by
rfl
theorem 2_eq_2 : 2 = 2 := by
exact (x_eq_x 2)
Here x_eq_x looks like a function, and in 2_eq_2's proof we apply it like a function.
danabramov|7 months ago