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A deep dive into Rust and C memory interoperability

154 points| hyperbrainer | 7 months ago |notashes.me

79 comments

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veber-alex|7 months ago

The reason you are not seeing crashes when allocating with Rust and freeing with C (or vice versa) is that by default Rust also uses the libc allocator.

https://stdrs.dev/nightly/x86_64-unknown-linux-gnu/src/std/s...

CupricTea|7 months ago

It's funny. When I first tried Rust in 2018 they were still statically linking jemalloc into every binary rustc compiled by default, and that alone very much put me off of the language for a while.

Apparently they did away with jemalloc in favor of the system allocator that same year but nonetheless when I came back to it years later I was very happy to learn of its removal.

mwkaufma|7 months ago

Lots of detail, little substance, and misleading section headers. GPT-generated red flags.

sjmulder|6 months ago

The interjected bullet point sections seem to be entirely LLM written and don't add anything, just meaningless interruption

eatonphil|7 months ago

One of the areas I wonder about this a lot is when integrating Rust code into Postgres which has its own allocator system. Mostly right now when we need to have complex data structures (non-Postgres data structures) that must live outside of the lexical scope we put them somewhere global and return a handle to the C code to reference the object. But with the upcoming support for passing an allocator to any data structure (in the Rust standard library anyway) I think this gets a lot easier?

tialaramex|7 months ago

For me the most interesting thing in Allocator is that it's allowed to say OK, you wanted 185 bytes but I only have a 256 byte allocation here, so, here is 256 bytes.

This means that e.g. a growable container type doesn't have to guess that your allocator probably loves powers of 2 and so it should try growing to 256 bytes not 185 bytes, it can ask for 185 bytes, get 256 and then pass that on to the user. Significant performance is left on the table when everybody is guessing and can't pass on what they know due to ABI limitations.

Rust containers such as Vec are already prepared to do this - for example Vec::reserve_exact does not promise you're getting exactly the capacity you asked for, it won't do the exponential growth trick because (unlike Vec::reserve) you've promised you don't want that, but it would be able to take advantage of a larger capacity provided by the allocator.

Arnavion|7 months ago

>But with the upcoming support for passing an allocator to any data structure (in the Rust standard library anyway) I think this gets a lot easier?

Yes and no. Even within libstd, some things require A=GlobalAlloc, eg `std::io::Read::read_to_end(&mut Vec<u8>)` will only accept Vec<u8, GlobalAlloc>. It cannot be changed to work with Vec<u8, A> because that change would make it not dyn-compatible (nee "object-safe").

And as you said it will cut you off from much of the third-party crates ecosystem that also assumes A=GlobalAlloc.

But if the subset of libstd you need supports A=!GlobalAlloc then yes it's helpful.

steveklabnik|7 months ago

I’m not sure what those two things have to do with each other, though I did just wake up. The only thing the new allocator stuff would give you is the ability to allocate a standard library data structure with the Postgres allocator. Scoping and handles and such wouldn’t change, and using your own data structures wouldn’t change.

It’s also very possible I’m missing something!

7e|7 months ago

Allocating memory with C and freeing it with Rust is silly. If you want to free a C-allocated pointer in Rust, just have Rust call back in to C. Expecting that allocators work identically in both runtimes is unreasonable and borderline insane. Heck, I wouldn't expect allocators to work the same even across releases of libc from the same vendor (or across releases of Rust's std).

rectang|7 months ago

I don't agree with your contemptuous framing. It's incorrect, and per the post's author, "dangerous" — but depending on your background it's not "silly" or "borderline insane". It's just naive, and writing a slab allocator as an exercise or making honest explorations like in this blog post will help cure the naivete.

benmmurphy|7 months ago

usually when interfacing with a library written in c the library will export functions for object destruction. it makes sense for that to be part of the interface instead of using the system allocator because it also gives the library freedom to do extra work during object destruction. if you have simple objects then its possible to just use the system allocator, but if you have graphs or trees of objects then its necessary to have a custom destroy function and there is always some risk in the future you might be forced to need to allocate more complex data structures that require multiple allocations.

Arnavion|7 months ago

The article is about how and why mixing allocators fails, not if it fails or how to fix the problem.

phkahler|7 months ago

Something I'd like to know for mixing Rust and C. I know it's possible to access a struct from both C and Rust code and have seen examples. But those all use accessor functions on the Rust side rather than accessing the members directly. Is it possible to define a structure in one of the languages and then via some wrapper or definitions be able to access it idiomatically in the other language? Can you point to some blog or documentation explaining how?

GrantMoyer|7 months ago

Rust bindgen[1] will automatically generate native Rust stucts (and unions) from C headers where possible. Note that c_int, c_char, etc. are just aliases for the corresponding native Rust types.

However, not all C constructs have idomatic Rust equivalents. For example, bitfields don't exist in Rust, and unlike Rust enums, C enums can have any value of the underlying type. And for ABI reasons, it's very commom in C APIs to use a pointer to an opaque type paired with what are effectively accessor function and methods, so mapping them to accessors and methods on a "Handle" type in Rust often is the most idomatic Rust representation of the C interface.

[1]: https://github.com/rust-lang/rust-bindgen

Arnavion|7 months ago

I don't know what examples you've been seeing. The interop structs are just regular Rust structs with the `#[repr(C)]` attribute applied to them, to ensure that the Rust compiler lays the struct out exactly as the C compiler for that target ABI would. Rust code can access their fields just fine. There's no strict need for accessor functions.

IshKebab|7 months ago

It's idiomatic to access struct fields directly in both languages. What more do you want?

commandersaki|7 months ago

Me: “If we do it via FFI then there’s a possibility the program may continue working (because the underlying structs share the same memory layout? right? …right?)”

I didn't understand what was being said here; was he suggesting that you call libc free using FFI; which would be fine? I understand the interviewer asked about using Rust dealloc though. I think the FFI bit is confusing me.

tracker1|7 months ago

Interesting read... and definitely good to know base of knowledge especially if you're working in transitional or mixed codebases.

sesm|7 months ago

Section named "The Interview Question That Started Everything" doesn't contain the interview question.

hyperbrainer|7 months ago

That's the first thing on the page.

> Interviewer: “What happens if you allocate memory with C’s malloc and try to free it with Rust’s dealloc, if you get a pointer to the memory from C?”

> Me: “If we do it via FFI then there’s a possibility the program may continue working (because the underlying structs share the same memory layout? right? …right?)”

PoignardAzur|7 months ago

It is, but yeah, the entire article's formatting is pretty weird.

ryanf|7 months ago

This article looked interesting, but I bounced off it because the author appears to have made heavy use of an LLM to generate the text. How can I trust that the content is worth reading if a person didn't care enough to write it themselves?

rectang|7 months ago

I find it hard to believe that an LLM would have come up with this quote to start the article:

> “Memory oppresses me.” - Severian, The Book of the New Sun

That sort of artistic/humourous flourish isn't in character for an LLM.

zem|7 months ago

it sounds nothing like AI to me! or AI has advanced to the point where it is hard to tell - e.g. I wouldn't expect a sentence like "You’re not just getting 64 bytes of memory. You’re entering into a complex contract with a specific allocator implementation." from one.

TechDebtDevin|7 months ago

Do you see Emojis in tables/code now and assume the person is using an llm? I dont really see it.

jokoon|7 months ago

Any insight on the quantity of paid rust job out there?

Tony_Delco|7 months ago

Fantastic opening line (“Memory oppresses me.”). If this article was written by an AI, it’s the best AI I’ve seen in months.

Seriously though: I already knew the “don’t mix allocators” rule, but I really enjoyed seeing such a careful and hands-on exploration of why it’s dangerous. Thanks for sharing it.