I'm saying that if I do a regular loop, something needs to explicitly mutate, either a reference or a value itself.
`for (var i = 0; i < n, i++)`, for example, requires that `i` mutate in order to keep track of the value so that the loop can eventually terminate. You could also do something like:
var i = new Obj();
while (!i.isDone()) {
//do some stuff
i = new Obj();
}
There, the reference to `i` is being mutated.
For tail recursion, it's a little different. If I did something like Factorial:
function factorial(n, acc) {
if (n <= 1) return acc;
return factorial(n - 1, acc * n);
}
Doing this, there's no explicit mutation. It might be happening behind the scenes, but everything there from the code perspective is creating a new value.
In something like Clojure, you might do something like
(defn vrange [n]
(loop [i 0 v []]
(if (< i n)
(recur (inc i) (conj v i))
v)))
(stolen from [1])
In this case, we're creating "new" structures on every iteration of the loop, so our code is "more pure", in that there's no mutation. It might be being mutated in the implementation but not from the author's perspective.
You could imagine a language like eg Python with a for-each loop that creates a new variable for each run through the loop body.
Basically, just pretend the loop body is a lambda that you call for each run through the loop.
It might make sense to think of the common loops as a special kind of combinator (like 'map' and 'filter', 'reduce' etc.) And just like you shouldn't write everything in terms of 'reduce', even though you perhaps could, you shouldn't write everything in terms of the common loops either.
Make up new combinators, when you need them.
For comparison, in Haskell we seldom use 'naked' recursion directly: we typically define a combinator and then use it.
That often makes sense, even if you only use the combinator once.
That's rebinding. Mutation is when you change the state of an object. Variables are not objects. You can't have a reference (aka pointer) pointing to a variable.
Nope. Loops are unnecessary unless you have mutation. If you don't mutate, there's no need to run the same code again: if the state of the world did not change during iteration 1, and you run the same code on it again, the state of the world won't change during iteration 2.
tombert|6 months ago
`for (var i = 0; i < n, i++)`, for example, requires that `i` mutate in order to keep track of the value so that the loop can eventually terminate. You could also do something like:
There, the reference to `i` is being mutated.For tail recursion, it's a little different. If I did something like Factorial:
Doing this, there's no explicit mutation. It might be happening behind the scenes, but everything there from the code perspective is creating a new value.In something like Clojure, you might do something like
(stolen from [1])In this case, we're creating "new" structures on every iteration of the loop, so our code is "more pure", in that there's no mutation. It might be being mutated in the implementation but not from the author's perspective.
I don't think I'm confusing anything.
[1] https://clojure.org/reference/transients
eru|6 months ago
Basically, just pretend the loop body is a lambda that you call for each run through the loop.
It might make sense to think of the common loops as a special kind of combinator (like 'map' and 'filter', 'reduce' etc.) And just like you shouldn't write everything in terms of 'reduce', even though you perhaps could, you shouldn't write everything in terms of the common loops either.
Make up new combinators, when you need them.
For comparison, in Haskell we seldom use 'naked' recursion directly: we typically define a combinator and then use it.
That often makes sense, even if you only use the combinator once.
ramchip|6 months ago
That's rebinding. Mutation is when you change the state of an object. Variables are not objects. You can't have a reference (aka pointer) pointing to a variable.
gpderetta|6 months ago
mrkeen|6 months ago