top | item 45123720 (no title) dosnem | 6 months ago This seems so simple but I’m totally not understanding it..If C = D^2, and you double compute, then 2C ==> 2D^2. How do you and the original author get 1.41D from 2D^2? discuss order hn newest yberreby|6 months ago If C ~ D^2, then D ~ sqrt(C).In other words, the required amount of data scales with the square root of the compute. The square root of 2 ~= 1.414. If you double the compute, you need roughly 1.414 times more data. dosnem|5 months ago Thanks for clarification!
yberreby|6 months ago If C ~ D^2, then D ~ sqrt(C).In other words, the required amount of data scales with the square root of the compute. The square root of 2 ~= 1.414. If you double the compute, you need roughly 1.414 times more data. dosnem|5 months ago Thanks for clarification!
yberreby|6 months ago
In other words, the required amount of data scales with the square root of the compute. The square root of 2 ~= 1.414. If you double the compute, you need roughly 1.414 times more data.
dosnem|5 months ago