top | item 45161358 (no title) b0gb | 5 months ago eazysecrets.forEach(secret => logMessage = logMessage.replaceAll(secret, '**')) discuss order hn newest mberning|5 months ago That presumes you know all secrets ahead of time. A risk in and of itself. But from a practical point of view you will never know all secrets, because they are generated constantly in real time. pluto_modadic|5 months ago I've known users to type passwords in the username field. you implicitly do NOT know all secrets (e.g., a password is hashed).secrets can also churn, so even if you did your example would require something besides an in-memory array.and, the final point: what if your secret masking code fails on an exception, too ;)
mberning|5 months ago That presumes you know all secrets ahead of time. A risk in and of itself. But from a practical point of view you will never know all secrets, because they are generated constantly in real time.
pluto_modadic|5 months ago I've known users to type passwords in the username field. you implicitly do NOT know all secrets (e.g., a password is hashed).secrets can also churn, so even if you did your example would require something besides an in-memory array.and, the final point: what if your secret masking code fails on an exception, too ;)
mberning|5 months ago
pluto_modadic|5 months ago
secrets can also churn, so even if you did your example would require something besides an in-memory array.
and, the final point: what if your secret masking code fails on an exception, too ;)