top | item 45446214 The antiderivative of 1/x is ln(x), not ln |x 2 points| max__dev | 5 months ago |blog.danielh.cc 2 comments order hn newest NoahZuniga|5 months ago Sir what you wrote down is equivalent to integral 1/x = ln|x| if x > 0 else ln|x| + pi*i gus_massa|5 months ago 1/x = ln|x| + C if x > 0ln|x| + pi*i + C or ln|x| - pi*i + C or is x < 0 (Protip: Choose C=-+pi*i)In reals ln|x| is fine.In complex, it's a mess https://en.wikipedia.org/wiki/Complex_logarithm
NoahZuniga|5 months ago Sir what you wrote down is equivalent to integral 1/x = ln|x| if x > 0 else ln|x| + pi*i gus_massa|5 months ago 1/x = ln|x| + C if x > 0ln|x| + pi*i + C or ln|x| - pi*i + C or is x < 0 (Protip: Choose C=-+pi*i)In reals ln|x| is fine.In complex, it's a mess https://en.wikipedia.org/wiki/Complex_logarithm
gus_massa|5 months ago 1/x = ln|x| + C if x > 0ln|x| + pi*i + C or ln|x| - pi*i + C or is x < 0 (Protip: Choose C=-+pi*i)In reals ln|x| is fine.In complex, it's a mess https://en.wikipedia.org/wiki/Complex_logarithm
NoahZuniga|5 months ago
gus_massa|5 months ago
ln|x| + pi*i + C or ln|x| - pi*i + C or is x < 0 (Protip: Choose C=-+pi*i)
In reals ln|x| is fine.
In complex, it's a mess https://en.wikipedia.org/wiki/Complex_logarithm