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strenholme | 4 months ago

As it turns out, it’s possible with Lua going back to 5.1 to not allow undeclared global variables:

https://www.lua.org/pil/14.2.html

That code looks like this in Lua 5.1:

  function set(name, val)
    rawset(_G, name, val or false)
  end
  function exists(name)
    if rawget(_G, name) then return true end
    return false
  end
  throwError = {__newindex = function(self,name) error("Unknown global " .. name) end,
                __index = function(self,name) error("Unknown global " .. name) end
  }
  setmetatable(_G,throwError)
Then, to use

  set("a") -- set"a" also works
  a = 1

discuss

order

ufo|4 months ago

Naturally, the main catch is that this only detects the violation at run-time. It also won't stop you from accidentally overwriting a global variable that already exists.

nmz|4 months ago

> It also won't stop you from accidentally overwriting a global variable that already exists.

That's also solvable using metatables.

Dylan16807|4 months ago

Do the declarations in 5.5 prevent overwriting? That sounds tricky to define and implement.