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mungoman2 | 4 months ago

As proposed in the article, calculating the area weights all points in the viewshed equally. I wonder if it makes sense to give more weight to far-away points? Or maybe less weight? Not sure! But would be interesting to explore and see if it gives anything.

discuss

tombh|4 months ago

I'm the author. Well there's actually a term in the kernel to normalise the surface area of each visible point by a factor of tan(1 radian): https://github.com/tombh/total-viewsheds/blob/main/crates/ke...

I don't know if that's related to what you're thinking about?