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hakken306 | 4 months ago
Assuming the chicken has a surface area A=1m^2 (corresponding to a perfectly spherical chicken of radius=25cm/diameter=50cm, a little bigger than usual) and is a perfect blackbody (just going to handwave this one).
with the incorrect temperature: A blackbody with T=165°C (438 K) and A=1m^2 radiates P=2090 W.
with the correct temperature: A blackbody with T=74°C (347 K) and A=1m^2 radiates P=824 W.
Also neglected is the incoming radiation from the ambient environment. Without this, the "power loss" is closer to measuring the chicken in deep interstellar space. from a room temperature environment: T=20°C (293 K) and A=1m^2 radiates P=419 W onto the chicken.
The net power loss of the cooling chicken on the kitchen counter is therefore something like 824-419 = 405W, rapidly decreasing as the temperature drops towards room temperature. e.g. at 50°C it's around 200W.
petters|4 months ago
bregma|4 months ago
fifticon|4 months ago
ptero|4 months ago
lelandfe|4 months ago
pansa2|4 months ago
Where did they even get 165F from in the first place? The “classic solution” article uses 400F, a much more appropriate oven temperature.
CitrusFruits|4 months ago