If your definition of "works" includes out of bounds memory access, use after free, etc., then yes. If your definition does not include those, then it demonstrably does not.
Alternately, maybe there's a spectrum of undesirable behaviors, some of which are preventable by choice of language, some of which aren't, and trying to reduce a complex set of tradeoffs to a simple binary of whether it "just works" only restates the conclusion someone has already come to because you need to actually reason about those tradeoffs to come to an informed decision of where to implicitly draw the line in the first place.
saghm|4 months ago
Alternately, maybe there's a spectrum of undesirable behaviors, some of which are preventable by choice of language, some of which aren't, and trying to reduce a complex set of tradeoffs to a simple binary of whether it "just works" only restates the conclusion someone has already come to because you need to actually reason about those tradeoffs to come to an informed decision of where to implicitly draw the line in the first place.
krior|4 months ago
uecker|4 months ago