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atrus | 4 months ago

A possible challenge, yes, but there exist 1500w, standard outlet hpwh, and it's a lot less common to not have any power near a water heater.

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quickthrowman|4 months ago

A 1500W electric water heater would be painful to use in a home. A typical 30-60 gallon EWH is 6kW.

And for the record, every single natural gas water heater is connected to 120V power for the ignition circuit.

adrianmonk|4 months ago

> every single natural gas water heater is connected to 120V power for the ignition circuit

Mine isn't. During a long power outage, I still had hot water.

I was a bit surprised the water heater was working since I was pretty sure it had an electronic control system. So I went and looked, and sure enough, it was electronic, and somehow the LED was flashing blue like normal!

It turns out the electronics are powered by a thermopile which is heated by the pilot light.

somehnguy|4 months ago

> And for the record, every single natural gas water heater is connected to 120V power for the ignition circuit.

This is incorrect. Multiple homes I've lived in had no electric to the water heater, including my current.

With a standing pilot a thermopile is used to generate the tiny bit of electric required for the control.

SigmundA|4 months ago

a 1500W heat pump water heater with a COP around 3 will put 5500 watts of heat into the water.

My Rheem hybrid 220v heat pump water heater only has a 500w compressor but puts 1500-2000 watts of heat into the water pulling it from the hot garage.

I have the choice to run it in high demand mode which will run both the heat pump and electric 4500w element for around 6kw of heat into the water if I need fast recovery.

tonyarkles|4 months ago

Keep in mind that there's going to be a CoP associated with a heat-pump water heater. Depending on (a bunch of factors) that 1500W HPWH could approach the performance of a 6kW standard EWH.

maxerickson|4 months ago

It's not uncommon for a gas heater to have an always on pilot.

harshreality|4 months ago

I think this is right...

kwatts_effective [kJ/s] * heating_time_minutes [min] * 60 [s/min] * COP = 4.184 [kJ/kg/K] * (T₁-T₀) [K] * gallon_capacity [gal] * 3.785 [L/gal] * 1 [kg/L]

6.6 kW, for... COP 4, T₁-T₀ = 30 [K] (lower value for warm climate), allowable 30 minute heating time, 50 gallon capacity. A cold climate could double that power requirement, or alternatively double the heating time.