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NobodyNada | 3 months ago

> There's a "logical" bit order that these operations follow, which starts with the MSBit and ends with the LSBit

Well, normally when bits are numbered, "bit 0" is the least significant bit. The MSB is usually written on the left, (such as for left and right shifts), but that doesn't necessarily make it "first" in my mind.

discuss

order

addaon|3 months ago

> Well, normally when bits are numbered, "bit 0" is the least significant bit.

IBM being abnormal. Can't argue with that.