(no title)
sriku | 2 months ago
Try writing a^b in integers and proving its correctness. The simple version works (based on a x a^(b-1)). But if you write an "optimised one" using (with handwaved details) (a^(b/2))^2 .... pulled some serious hair trying to prove this function works.
sriku|2 months ago
fithisux|2 months ago