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clausecker | 2 months ago

You can do it like this, assuming A is the mask of newlines and B is the mask of non-spaces.

1. Compute M1 = ~A & ~B, which is the mask of all spaces that are not newlines 2. Compute M2 = M1 + (A << 1) + 1, which is the first non-space or newline after each newline and then additional bits behind each such newline. 3. Compute M3 = M2 & ~M1, which removes the junk bits, leaving only the first match in each section

Here is what it looks like:

    10010000 = A
    01100110 = B
    00001001 = M1 = ~A & ~B
    00101010 = M2 = M1 + (A << 1) + 1
    00100010 = M3 = M2 & ~M1
Note that this code treats newlines as non-spaces, meaning if a line comprises only spaces, the terminating NL character is returned. You can have it treat newlines as spaces (meaning a line of all spaces is not a match) by computing M4 = M3 & ~A.

discuss

order

zokrezyl|2 months ago

Thanks for the suggestion. Indeed, that would be the first approach. That is how I started. This is however not considering the state (am I inside a 'statement' or not)

statement meaning string from first non-space till next EOL or EOF.

Problem starts when you need to cover the "corner cases". Without the corner cases the algo is not algo.

zokrezyl|2 months ago

Do you mind trying out your solution? The code is in https://github.com/zokrezyl/yaal-cpp-poc Thanks a lot!

Obviously if your solutions gets closed to the memory bandwith limit, we will proudly mention it!

clausecker|2 months ago

This does track the state. If you want to track it across multple vectors of input, you'll need to carry it over manually.