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zero-sharp | 1 month ago

If I understand this correctly, it translates Rocq to C++? Took me several minutes to even understand what this is. Why is it called an extraction system? Who is this for?

I'm confused.

edit: I had to dig into the author's publication list:

https://joomy.korkutblech.com/papers/crane-rocqpl26.pdf

Testing remains a fundamental practice for building confidence in software, but it can only establish correctness over a finite set of inputs. It cannot rule out bugs across all possible executions. To obtain stronger guarantees, we turn to formal verification, and in particular to certified programming techniques that allow us to de- velop programs alongside mathematical proofs of their correctness. However, there is a significant gap between the languages used to write certified programs and those relied upon in production systems. Bridging this gap is crucial for bringing the benefits of formal verification into real-world software systems.

discuss

order

cobbal|1 month ago

That's essentially correct. Extraction is a term in roqc. A rocq program contains both a computational part, and proofs about that computation, all mixed together in the type system. Extraction is the automated process of discarding the proofs and writing out the computational component to a more conventional (and probably more efficient) programming language.

The original extractor was to ocaml, and this is a new extractor to c++.

joomy|1 month ago

Just like JavaScript folks like calling their compilers "transpiler", proof assistants folks like calling their compilers "extraction". Essentially it's a compiler from a high-level language to a slightly lower-level, but still reasonably high-level language.

GregarianChild|1 month ago

I would phrase it a little different.

Simplifying a bit, a compiler tr(.) translates from a source language L1 to a target language L2 such that

    semantics(P) == semantics(tr(P))
for all programs in L1. In contrast, and again simplifying a bit, extraction extr(.) assumes not only language L1 and L2 as above, but, at least conceptually, also corresponding specification languages S1 and S2 (aka logics). Whenever P |= phi and extr(P, phi) = (P', phi') then not just

    semantics(P) == semantics(P') 
as in compilation, but also

    semantics(phi) = semantics(phi'), 
hence P' |= phi'.

I say "at least conceptually" above, because this specificatyion is often not lowered into a different logical formalism. Instead it is implied / assumed that if the extraction mechanism was correct, then the specification could also be lowered ...

GregarianChild|1 month ago

I have another question, the abstract of your paper says that you "provide concurrency primitives in Rocq". But this is not really explained in the text. What are those "concurrency primitives"?