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phicoh | 9 days ago
As far as I can tell, Rust can do what it is in your example (which different syntax of course) except for this particular way of initializing an array.
To me, that seems like a pretty minor syntax issue to that could be added to Rust if there would be a lot of demand for initializing arrays this way.
flohofwoe|9 days ago
E.g. notice how here in Rust each nested struct needs a type annotation, even though the compiler could trivially infer the type. Rust also cannot initialize arrays with random access directly, it needs to go through an expression block. Finally Rust requires `..Default::default()`:
https://github.com/floooh/sokol-rust/blob/f824cd740d2ac96691...
Zig has most of the same issues as Rust, but at least the compiler is able to infer the nested struct types via `.{ }`:
https://github.com/floooh/sokol-zig/blob/17beeab59a64b12c307...
I don't have C++ code around, but compared to C99 it has the following restrictions:
- designators must appear in order (a no-go for any non-trivial struct)
- cannot chain designators (e.g. `.a.b.c = 123`)
- doesn't have the random array access syntax via `[index]`
> ...like a pretty minor syntax issue...
...sure, each language only has a handful minor syntax issues, but these papercuts add up to a lot of syntax noise to sift through when compared to the equivalent C99 code.
phicoh|9 days ago
I have to admit, the ..Default::default() syntax is pretty ugly.
In theory Rust could do "let x: Foo = _ { field }" and "Foo { field: _ { bar: 1 } }". That doesn't even change the syntax. Its just whether enough people care.