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Gehinnn | 8 days ago
Otherwise, if you check that no custom axiom has been used (via print axioms), the proof is valid.
It's easy to construct such an example: Prove that for all a, b, c and n between 3 and 10^5, a^n=b^n+c^n has no solution. The unmeaningful proof would enumerate all ~10^20 cases and proof them individually. The meaningful (and probably even shorter) proof would derive this from Fermat's theorem after proving that one.
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